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Question

S.I. an ₹ $1000 @ 10 \%$ p.a. after 4 years

$=\frac{1000 	imes 4 	imes 10}{100}=₹ 400$

C.I. on ₹ $1000 @ 10 \%$ p.a. after 4 years.

$=1000\

Vedclass · Accepted Answer

$64.10$

Vedclass · Answer

S.I. an ₹ $1000 @ 10 \%$ p.a. after 4 years

$=\frac{1000 	imes 4 	imes 10}{100}=₹ 400$

C.I. on ₹ $1000 @ 10 \%$ p.a. after 4 years.

$=1000\left[\left(1+\frac{10}{100}ight)^{4}-1ight]=1000\left[\left(\frac{11}{10}ight)^{4}-1ight]$

$=\frac{1000}{10^{4}}\left(11^{4}-10^{4}ight)=\frac{1000}{10000}(121+100)(11+10) 1$

$=\frac{1}{10} 	imes 221 	imes 21=\frac{4641}{10}=₹ 464.10$

Hence C.I.- S.I. $=464.10-400=₹ 64.10$

What will be the difference between simple and compound interest (In ₹) @ $10 \%$ per annum on a sum of ₹ $1000$ after $4$ years?

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