What will be the difference in volume of water when it is heated from $0\,^oC$ to $10\,^oC$ ?
What will be the difference in volume of water when it is heated from $0\,^oC$ to $10\,^oC$ ?
Initially (from $0^{\circ} \mathrm{C}$ to $4^{\circ} \mathrm{C}$ ) volume decreases and then (from $4^{\circ} \mathrm{C}$ to $10^{\circ} \mathrm{C}$ ) volume increase.
Similar Questions
A metal ball immersed in alcohol weighs ${W_1}$ at $0°C$ and ${W_2}$ at $59°C.$ The coefficient of cubical expansion of the metal is less than that of alcohol. Assuming that the density of metal is large compared to that of alcohol, it can be shown that
A metal ball immersed in alcohol weighs ${W_1}$ at $0°C$ and ${W_2}$ at $59°C.$ The coefficient of cubical expansion of the metal is less than that of alcohol. Assuming that the density of metal is large compared to that of alcohol, it can be shown that
A bimetallic strip consists of metals $X$ and $Y$. It is mounted rigidly at the base as shown. The metal $X$ has a higher coefficient of expansion compared to that for metal $Y$. When the bimetallic strip is placed in a cold bath:
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- [AIIMS 2006]
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Two rods, one of aluminum and the other made of steel, having initial length ${l_1}$ and ${l_2}$ are connected together to form a single rod of length ${l_1} + {l_2}$. The coefficients of linear expansion for aluminum and steel are ${\alpha _a}$ and ${\alpha _s}$ respectively. If the length of each rod increases by the same amount when their temperature are raised by ${t^o}C$, then find the ratio $\frac{{{l_1}}}{{({l_1} + {l_2})}}$
Two rods, one of aluminum and the other made of steel, having initial length ${l_1}$ and ${l_2}$ are connected together to form a single rod of length ${l_1} + {l_2}$. The coefficients of linear expansion for aluminum and steel are ${\alpha _a}$ and ${\alpha _s}$ respectively. If the length of each rod increases by the same amount when their temperature are raised by ${t^o}C$, then find the ratio $\frac{{{l_1}}}{{({l_1} + {l_2})}}$
- [IIT 2003]