What will be ratio of distance moved by a freely falling body from rest in 4^{th} and 5^{th} seconds

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2.Motion in Straight Line

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What will be the ratio of the distance moved by a freely falling body from rest in $4^{th}$ and $5^{th}$ seconds of journey ?

A

$7 : 9$

B

$4:5$

C

$16: 25$

D

$1:1$

(AIPMT-1989)

Solution

Distance covered in $n^{t h}$ second is given by

$s_{n}=u+\frac{a}{2}(2 n-1)$

Given : $u=0, a=g$

$\therefore s_{4}=\frac{g}{2}(2 \times 4-1)=\frac{7 g}{2}$

$s_{5}=\frac{g}{2}(2 \times 5-1)=\frac{9 g}{2}$

$\frac{s_{4}}{s_{5}}=\frac{7}{9}$

Standard 11

Physics

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