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1. Electric Charges and Fields
easy
When ${10^{19}}$ electrons are removed from a neutral metal plate, the electric charge on it is
A
$-1.6 \,C$
B
$+ 1.6 \,C$
C
$10^{+19}\, C$
D
$10^{-19} \,C$
Solution
(b) By using $Q = ne \Rightarrow Q = {10^{19}} \times 1.6 \times {10^{ – 19}}$ $ = + 1.6\,C$.
Standard 12
Physics
