When a body is thrown with a velocity u making an angle θ with horizontal plane, maximum distance c

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3-2.Motion in Plane

easy

When a body is thrown with a velocity $u$ making an angle $\theta $ with the horizontal plane, the maximum distance covered by it in horizontal direction is

A

$\frac{{{u^2}\sin \theta }}{g}$

B

$\frac{{{u^2}\sin 2\theta }}{{2g}}$

C

$\frac{{{u^2}\sin 2\theta }}{g}$

D

$\frac{{{u^2}\cos 2\theta }}{g}$

Solution

(c) in horizontal direction velocity is constant as there is no acceleration

$v=u \cos \theta$

time of flight $=\frac{2 u \sin \theta}{g}$

range emaximum distance traveled in horizontal direction

$=v t=\frac{u^{2} \sin 2 \theta}{g}$

Standard 11

Physics

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