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4.Moving Charges and Magnetism
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When a charged particle moving with velocity $\vec V$ is subjected to a magnetic field of induction $\vec B$ , the force on it is non-zero. This implies the
A
Angle between $\vec V$ and $\vec B$ is necessary $90^o$
B
Angle between $\vec V$ and $\vec B$ can have any value other than $90^o$
C
Angle between $\vec V$ and $\vec B$ can have any value other than zero and $180^o$
D
Angle between $\vec V$ and $\vec B$ is either zero or $180^o$
Solution
$\overrightarrow {\text{F}} = {\text{q}}(\overrightarrow {\text{v}} \times \overrightarrow {\text{B}} ) = {\text{qvB}}\sin \theta \,\widehat {\text{n}}$
Therefore when $\theta=0^{\circ}$ or $\theta=180^{\circ}, \quad \mathrm{F}=0$
Standard 12
Physics
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