when a man eats $100\,g$ of ice in a minutes, how much power will he get ? The latent heat of ice is $80\,cal/g$.
when a man eats $100\,g$ of ice in a minutes, how much power will he get ? The latent heat of ice is $80\,cal/g$.
Mass of ice eaten by the man per second.
$m =\frac{100}{60}=\frac{5}{3}=\frac{5}{3} g / m$
Latent heat of ice,
$L =80 cal / g$
Therefore, energy required per second by the man in eating the ice, i.e., power developed by the man,
$= mL =\frac{5}{3} \times 80 cal / s$
$=\frac{50 \times 80}{3} \times 4.2 J / s =560 W$
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