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11.Thermodynamics
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When an ideal diatomic gas is heated at constant pressure, the fraction of the heat energy supplied which increases the internal energy of the gas, is
A
$\frac{2}{5}$
B
$\frac{3}{5}$
C
$\frac{3}{7}$
D
$\frac{5}{7}$
Solution
When a gas is heated at constant pressure then its one part goes to increase the internal energy and another part for work done against external pressure i.e.
$(\Delta Q)_{p}=\Delta U+\Delta W$
$\mu C_{p} \Delta T=\mu C_{v} \Delta T+P \Delta V$
So fraction of energy that goes to increase the internal energy
$\frac{\Delta U}{(\Delta Q)_{p}}=\frac{C_{v}}{C_{p}}=\frac{1}{\gamma}=\frac{5}{7}$
[As $\mathrm{y}=7 / 5$ for diatomic gas]
Standard 11
Physics
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