When body is at rest or it is in uniform motion, no force act on it.
When body is at rest or in uniform motion gravitational force act on it. Forces like frictional force, viscous force act on body.
When object is at rest or in uniform motion, resultant force of various external force acting on it is zero.
Consider book at rest on horizontal surface following force act on it.
$(1)$ Weight of body $(W)$ in downward direction.
$(2)$ Normal force ($R$ or $N$) in upward direction.
Here book is at rest hence, $\mathrm{W}=\mathrm{R}$.
Effect of both force cancel out each other. Hence, book is at rest.
Actually it should be like this, considering book at rest by Newton's first law of motion resultant of external force acting on body must be zero. This suggest that normal force and weight should be equal and in opposite direction.
A boy is hanging from branch of a tree as shown. Angle between his arm, for tension to be maximum in arms must be ............ $^o$
Figure shows $(x,\, t)$, $(y,\, t)$ diagram of a particle moving in $2-$ dimensions.
If the particle has a mass of $500\,g$, find the force (direction and magnitude) acting on the particle.
A block of mass $M$ is pulled along a horizontal frictionless surface by a rope of mass $M / 2$. If a force $2 Mg$ is applied at one end of the rope, the force which the rope exerts on the block is -
An $80\, kg$ person is parachuting and is experiencing a downward acceleration of $2.8\, m/s^2$. The mass of the parachute is $5\, kg$. The upward force on the open parachute is ........... $N$ (Take $g = 9.8\, m/s^2$)