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p-Block Elements - I
easy
Which of the following compound is formed in borax bead test?
A
Metaborate
B
Tetraborate
C
Double oxide
D
Orthoborate
Solution
Answer:- (A) Metaborate
On heating, borax loses water of crystallisation and swells up to form fluffy mass. On further heating, it melts to give a clear liquid which solidifies to a transparent glossy bead consisting of sodium metaborate and boric unhydride.
$\mathrm{Na}_{2} \mathrm{B}_{4} \mathrm{O}_{7} \cdot 10 \mathrm{H}_{2} \mathrm{O} \stackrel{\Delta}{\longrightarrow} \mathrm{Na}_{2} \mathrm{B}_{4} \mathrm{O}_{7} \stackrel{\Delta}{\longrightarrow}{\underset { Sodium Metaborate }{2 \mathrm{NaBO}_{2}}}+\mathrm{B}_{2} \mathrm{O}_{3}$
Thus, Metaborate is formed.
Standard 11
Chemistry