Which of the following is correct
$\tan 1 > \tan 2$
$\tan 1 = \tan 2$
$\tan 1 < \tan 2$
$\tan 1 = 1$
As, $\tan 1=1.557$
and $\tan 2=-2.185$
Clearly, $\tan 1 > \tan 2$
$\sin \left( {\frac{\pi }{{10}}} \right)\sin \left( {\frac{{3\pi }}{{10}}} \right) = $
If $\theta $ and $\phi $ are angles in the $1^{st}$ quadrant such that $\tan \theta = 1/7$ and $\sin \phi = 1/\sqrt {10} $.Then
If $\sin \theta = \frac{{ – 4}}{5}$ and $\theta $ lies in the third quadrant, then $\cos \frac{\theta }{2} = $
Convert $6$ radians into degree measure.
If ${\rm{cosec }}A + \cot A = \frac{{11}}{2},$ then $\tan A = $
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