Cryolite; $\mathrm{Na}_{3} \mathrm{AlF}_{6}$, sodium hexafluoroaluminate.

Mica: $\mathrm{KAl}_{3} \mathrm{Si}_{3} \mathrm{O} 10(\mathrm{OH})_{2}$ Basic potassium aluminum silicate

Feldspars $\mathrm{KAlSi}_{3} \mathrm{O}_{8} \mathrm{NaAlSi}_{3} \mathrm{O}_{8} \mathrm{CaAl}_{2} \mathrm{Si}_{2} \mathrm{O}_{8}$

fluorspar: $\mathrm{CaF}_{2}, \mathrm{calcium}$ fluoride. So only in fluorspar there is no Al present.

Hence option D is correct.