Consider the compounds, $BCl_3$, and $CCl_4$ How will they behave with water ? Justify.

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In $BCl _3, B$ atom is electron deficient and accepts an electron pair from water. It is hydrolyzed to boric acid.

$BCl _3+3 H _2 O \rightarrow H _3 BO _3+3 HCl$

On the other hand, $CCl _4$ is an electron precise molecule. $C$ has completed its octet and cannot expand its valency shell due to absence of $d$ orbitals. Hence, it can neither donate nor accept electrons. Hence, $CCl _4$ is not hydrolyzed.

Similar Questions

Explain the nature of boric acid as a Lewis acid in water. 

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Taking stability as the factor, which one of the following represents correct relationship?

  • [NEET 2023]

Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R$.

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Reason $R$ : Boric acid is not able to release $H ^{+}$ion on its own. It receives $OH ^{-}$ion from water and releases $H ^{+}$ion.

In the light of the above statements, choose the most appropriate answer from the options given below.

  • [JEE MAIN 2022]