Consider the compounds, $BCl_3$, and $CCl_4$ How will they behave with water ? Justify.
Consider the compounds, $BCl_3$, and $CCl_4$ How will they behave with water ? Justify.
In $BCl _3, B$ atom is electron deficient and accepts an electron pair from water. It is hydrolyzed to boric acid.
$BCl _3+3 H _2 O \rightarrow H _3 BO _3+3 HCl$
On the other hand, $CCl _4$ is an electron precise molecule. $C$ has completed its octet and cannot expand its valency shell due to absence of $d$ orbitals. Hence, it can neither donate nor accept electrons. Hence, $CCl _4$ is not hydrolyzed.
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