Consider the compounds, $BCl_3$, and $CCl_4$ How will they behave with water ? Justify.
In $BCl _3, B$ atom is electron deficient and accepts an electron pair from water. It is hydrolyzed to boric acid.
$BCl _3+3 H _2 O \rightarrow H _3 BO _3+3 HCl$
On the other hand, $CCl _4$ is an electron precise molecule. $C$ has completed its octet and cannot expand its valency shell due to absence of $d$ orbitals. Hence, it can neither donate nor accept electrons. Hence, $CCl _4$ is not hydrolyzed.
Explain the nature of boric acid as a Lewis acid in water.
The structure of diborane contains :-
Complete the following chemical equations :
$Z + 3LiAl{H_4} \to X + 3LiF + 3Al{F_3}$
$X + 6{H_2}O \to Y + 6{H_2}$
$3X + 3{O_2}\xrightarrow{\Delta }{B_2}{O_3} + 3{H_2}O$
Taking stability as the factor, which one of the following represents correct relationship?
Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A$ : Boric acid is a weak acid
Reason $R$ : Boric acid is not able to release $H ^{+}$ion on its own. It receives $OH ^{-}$ion from water and releases $H ^{+}$ion.
In the light of the above statements, choose the most appropriate answer from the options given below.