If $A = \left( {\begin{array}{*{20}{c}}1&2&3\\3&1&2\\2&3&1\end{array}} \right)$ and $B = \left( {\begin{array}{*{20}{c}}{ – 5}&7&1\\1&{ – 5}&7\\7&1&{ – 5}\end{array}} \right)$ then $AB$ is equal to

The order of $[x\,y\,z]\,\,\left[ {\begin{array}{*{20}{c}}a&h&g\\h&b&f\\g&f&c\end{array}} \right]\,\left[ \begin{array}{l}x\\y\\z\end{array} \right]$ is

If $2X – \left[ {\begin{array}{*{20}{c}}1&2\\7&4\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}3&2\\0&{ – 2}\end{array}} \right]$, then $X$  is equal to

If $A = \left[ {\begin{array}{*{20}{c}}2&0&0\\0&2&0\\0&0&2\end{array}} \right],$then ${A^5} = $

If $A = \left[ {\begin{array}{*{20}{c}}i&0\\0&{ – i}\end{array}} \right],B = \left[ {\begin{array}{*{20}{c}}0&i\\i&0\end{array}} \right]$, where $i = \sqrt { – 1} $, then the correct relation is