Why atoms are electrical neutral ?
Why atoms are electrical neutral ?
Similar Questions
If in nature there may not be an element for which the principal quantum number $n > 4,$ then the total possible number of elements will be
If in nature there may not be an element for which the principal quantum number $n > 4,$ then the total possible number of elements will be
- [IIT 1983]
Hydrogen $(H)$, deuterium $(D)$, singly ionized helium $(He^+)$ and doubly ionized lithium $(Li^{++})$ all have one electron around the nucleus. Consider $n = 2$ to $n = 1$ transition. The wavelengths of emitted radiations are $\lambda_1, \lambda_2 \lambda_3$ and $\lambda_4$ respectively.
Hydrogen $(H)$, deuterium $(D)$, singly ionized helium $(He^+)$ and doubly ionized lithium $(Li^{++})$ all have one electron around the nucleus. Consider $n = 2$ to $n = 1$ transition. The wavelengths of emitted radiations are $\lambda_1, \lambda_2 \lambda_3$ and $\lambda_4$ respectively.
In an atom for the electron to revolve around the nucleus, the necessary centripetal force is obtained from the following force exerted by the nucleus on the electron
In an atom for the electron to revolve around the nucleus, the necessary centripetal force is obtained from the following force exerted by the nucleus on the electron
The figure represents the observed intensity of $X-$rays emitted by an $X-$ray tube, as a function of wavelength. The sharp peaks $A$ and $B$ denote
The figure represents the observed intensity of $X-$rays emitted by an $X-$ray tube, as a function of wavelength. The sharp peaks $A$ and $B$ denote
Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is
Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is