Gujarati
12.Atoms
normal

The following diagram indicates the energy levels of a certain atom when the system moves from $4E$ level to $E$. A photon of wavelength $\lambda _1$ is emitted. The wavelength of photon produced during it's transition from $\frac{7}{3}E$ level to $E$ is $\lambda_2$. The ratio $\frac{{{\lambda _1}}}{{{\lambda _2}}}$ will be

A

$\frac{9}{4}$

B

$\frac{4}{9}$

C

$\frac{3}{2}$

D

$\frac{7}{3}$

Solution

(b) Transition from $4E$ to $E$
$(4E – E) = \frac{{hc}}{{{\lambda _1}}}$ ==> ${\lambda _1} = \frac{{hc}}{{3E}}$ …… $(i)$
Transition from $\frac{7}{3}E$ to $E$
$\left( {\frac{7}{3}E – E} \right) = \frac{{hc}}{{{\lambda _2}}}$ ==> ${\lambda _2} = \frac{{3hc}}{{4E}}$ …… $(i)$
From equation $(i)$ and $(ii)$ $\frac{{{\lambda _1}}}{{{\lambda _2}}} = \frac{4}{9}$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.