- Home
- Standard 12
- Physics
12.Atoms
normal
The following diagram indicates the energy levels of a certain atom when the system moves from $4E$ level to $E$. A photon of wavelength $\lambda _1$ is emitted. The wavelength of photon produced during it's transition from $\frac{7}{3}E$ level to $E$ is $\lambda_2$. The ratio $\frac{{{\lambda _1}}}{{{\lambda _2}}}$ will be

A
$\frac{9}{4}$
B
$\frac{4}{9}$
C
$\frac{3}{2}$
D
$\frac{7}{3}$
Solution
(b) Transition from $4E$ to $E$
$(4E – E) = \frac{{hc}}{{{\lambda _1}}}$ ==> ${\lambda _1} = \frac{{hc}}{{3E}}$ …… $(i)$
Transition from $\frac{7}{3}E$ to $E$
$\left( {\frac{7}{3}E – E} \right) = \frac{{hc}}{{{\lambda _2}}}$ ==> ${\lambda _2} = \frac{{3hc}}{{4E}}$ …… $(i)$
From equation $(i)$ and $(ii)$ $\frac{{{\lambda _1}}}{{{\lambda _2}}} = \frac{4}{9}$
Standard 12
Physics
Similar Questions
normal