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10-2.Transmission of Heat
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Wires $A$ and $B$ have identical lengths and have circular cross-sections. The radius of $A$ is twice the radius of $B$ $i.e.$ ${r_A} = 2{r_B}$. For a given temperature difference between the two ends, both wires conduct heat at the same rate. The relation between the thermal conductivities is given by
A
${K_A} = 4{K_B}$
B
${K_A} = 2{K_B}$
C
${K_A} = {K_B}/2$
D
${K_A} = {K_B}/4$
Solution
(d) $\frac{Q}{t} = \frac{{KA\Delta \theta }}{l} \Rightarrow \frac{{{K_A}}}{{{K_B}}} = \frac{{{A_B}}}{{{A_A}}} = {\left( {\frac{{{r_B}}}{{{r_B}}}} \right)^2} = \frac{1}{4} \Rightarrow {K_A} = \frac{{{K_B}}}{4}$
Standard 11
Physics
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