Without actually calculating the cubes, find the value of each of the following
$(14)^{3}+(27)^{3}-(41)^{3}$
$-46494$
$45745$
$-32514$
$44586$
If $p(x)=x^{2}-4 x+3,$ evaluate $: p(2)-p(-1)+p\left(\frac{1}{2}\right)$
Factorise the following:
$16 x^{2}+4 y^{2}+9 z^{2}-16 x y-12 y z+24 x z$
Expand
$(3 x-2)(3 x-6)$
Evaluate the following using suitable identities
$(105)^{3}$
Evaluate $(132)^{2}$ by using suitable identities
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