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1.Set Theory
easy
Write the solution set of the equation ${x^2} + x - 2 = 0$ in roster form.
A
$(1,-2)$
B
$(1,-2)$
C
$(1,-2)$
D
$(1,-2)$
Solution
The given equation can be written as
$\left( {x – 1} \right)\left( {x – 2} \right) = 0,$ i.e., $x=1,-2 $
Therefore, the solution set of the given equation can be written in roster form as $\{ 1, – 2\} $
Standard 11
Mathematics
Similar Questions
Match each of the set on the left in the roster form with the same set on the right described in set-builder form:
$(i)$ $\{1,2,3,6\}$ | $(a)$ $\{ x:x$ is a prime number and a divisor $6\} $ |
$(ii)$ $\{2,3\}$ | $(b)$ $\{ x:x$ is an odd natural number less than $10\} $ |
$(iii)$ $\{ M , A , T , H , E , I , C , S \}$ | $(c)$ $\{ x:x$ is natural number and divisor of $6\} $ |
$(iv)$ $\{1,3,5,7,9\}$ | $(d)$ $\{ x:x$ a letter of the work $\mathrm{MATHEMATICS}\} $ |
medium