3.Trigonometrical Ratios, Functions and Identities
normal

$\frac{{\sin {{81}^o} + \cos {{81}^o}}}{{\sin {{81}^o} - \cos {{81}^o}}}$ is equal to

A

$cot9^o$

B

$tan9^o$

C

$cot54^o$

D

$tan54^o$

Solution

$E=\frac{1+tan\,9^o}{1-tan\,9^o} =tan\, 54^o$

Standard 11
Mathematics

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