540 g of ice at 0 ^oC is mixed with 540 g water at 80 ^oC . final temperature of m

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10-1.Thermometry, Thermal Expansion and Calorimetry

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$540\ g$ of ice at $0\ ^oC$ is mixed with $540\ g$ water at $80\ ^oC$. The final temperature of the mixture is

A

$0\ ^oC$

B

$40\ ^oC$

C

$80\ ^oC$

D

Less than $0\ ^oC$

Solution

Let us assume that the complete ice melts and final temperature is $T.$ Then, by principle of calorimetry.

$540(1)(80-T)=540(80)+540(0.5)(T-0)$

$80-T=80+0.5 T$

$T=0^{0} C$

Hence, all the ice just melts and final temperature is $0^{\circ} \mathrm{C}$

Standard 11

Physics

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