$S_1$ and $S_2$ are two equipotential surfaces on which the potentials are not equal. Which of the statement is incorrect ?
 

  • A

    $S_1$ and $S_2$ both cannot intersect

  • B

    $S_1$ and $S_2$ both cannot be plane surfaces

  • C

    in the region between $S_1$ and $S_2$ , the field is maximum where they are closest to each other

  • D

    a line of force from $S_1$ to $S_2$ must be perpendicular to both

Similar Questions

An infinite non-conducting sheet has a surface charge density $\sigma  = 0.10\, \mu C/m^2$ on one side. How far apart are equipotential surfaces whose potentials differ by $50\, V$

Draw an equipotential surface for a point charge.

Assertion : Two equipotential surfaces cannot cut each other.

Reason : Two equipotential surfaces are parallel to each other.

  • [AIIMS 2011]

Two point charges of magnitude $+q$ and $-q$ are placed at $\left( { - \frac{d}{2},0,0} \right)$ and $\left( {\frac{d}{2},0,0} \right)$, respectively. Find the equation of the equipotential surface where the potential is zero.

The diagrams below show regions of equipotentials.A positive charge is moved from $A$ to $B$ in each diagram. 

  • [NEET 2017]