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2. Electric Potential and Capacitance
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$S_1$ and $S_2$ are two equipotential surfaces on which the potentials are not equal. Which of the statement is incorrect ?
A
$S_1$ and $S_2$ both cannot intersect
B
$S_1$ and $S_2$ both cannot be plane surfaces
C
in the region between $S_1$ and $S_2$ , the field is maximum where they are closest to each other
D
a line of force from $S_1$ to $S_2$ must be perpendicular to both
Solution
As we know that two equipotential surfaces can not intersect each other and lines of force are always perpendicular to the equipotential surface.
When two equipotential lines close together, the slope will be steep. So, close equipotential surfaces indicate a maximum electric field. $\left(E=-\frac{d V}{d x}\right)$
Ans: $(A),(C),(D)$ is correct ans
Standard 12
Physics
