Given below are two statements: one is labelled a
Assertion $(A)$ and the other is labelled as Reason$(R)$
$Assertion$ $(A)$ : Work done by electric field on moving a positive charge on an equipotential surface is always zero.
$Reason$ $(R)$ : Electric lines of forces are always perpendicular to equipotential surfaces.
In the light of the above statements, choose the most appropriate answer from the options given below
Given below are two statements: one is labelled a
Assertion $(A)$ and the other is labelled as Reason$(R)$
$Assertion$ $(A)$ : Work done by electric field on moving a positive charge on an equipotential surface is always zero.
$Reason$ $(R)$ : Electric lines of forces are always perpendicular to equipotential surfaces.
In the light of the above statements, choose the most appropriate answer from the options given below
- [JEE MAIN 2024]
- A
Both $(A)$ and $(R)$ are correct but $(R)$ is not the correct explanation of $(\mathrm{A})$
- B
$(A)$ is correct but $(R)$ is not correct
- C
$(A)$ is not correct but $(R)$ is correct
- D
Both $(A)$ and $(R)$ are correct and $(R)$ is the correct explanation of $(A)$
Similar Questions
A point charge $+Q$ is placed just outside an imaginary hemispherical surface of radius $R$ as shown in the figure. Which of the following statements is/are correct?
(IMAGE)
$[A]$ The electric flux passing through the curved surface of the hemisphere is $-\frac{\mathrm{Q}}{2 \varepsilon_0}\left(1-\frac{1}{\sqrt{2}}\right)$
$[B]$ Total flux through the curved and the flat surfaces is $\frac{Q}{\varepsilon_0}$
$[C]$ The component of the electric field normal to the flat surface is constant over the surface
$[D]$ The circumference of the flat surface is an equipotential
A point charge $+Q$ is placed just outside an imaginary hemispherical surface of radius $R$ as shown in the figure. Which of the following statements is/are correct?
(IMAGE)
$[A]$ The electric flux passing through the curved surface of the hemisphere is $-\frac{\mathrm{Q}}{2 \varepsilon_0}\left(1-\frac{1}{\sqrt{2}}\right)$
$[B]$ Total flux through the curved and the flat surfaces is $\frac{Q}{\varepsilon_0}$
$[C]$ The component of the electric field normal to the flat surface is constant over the surface
$[D]$ The circumference of the flat surface is an equipotential
- [IIT 2017]
Electric field is always ...... to the equipotential surface at every point. (Fill in the gap)
Electric field is always ...... to the equipotential surface at every point. (Fill in the gap)
Assertion $(A):$ A spherical equipotential surface is not possible for a point charge.
Reason $(R):$ A spherical equipotential surface is possible inside a spherical capacitor.
Assertion $(A):$ A spherical equipotential surface is not possible for a point charge.
Reason $(R):$ A spherical equipotential surface is possible inside a spherical capacitor.
- [AIIMS 2015]
Define an equipotential surface.
Define an equipotential surface.
Prove that a closed equipotential surface with no charge within itself must enclose an equipotential volume.
Prove that a closed equipotential surface with no charge within itself must enclose an equipotential volume.