P{Kₐ} value for acetic acid at experimental temperature is 5 . percentage hydrolysis of 0.1,,M sod

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6-2.Equilibrium-II (Ionic Equilibrium)

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$p{K_a}$ value for acetic acid at the experimental temperature is $5$. The percentage hydrolysis of $0.1\,\,M$ sodium acetate solution will be

A

$1 \times {10^{ - 4}}$

B

$1 \times {10^{ - 2}}$

C

$1 \times {10^{ - 3}}$

D

$1 \times {10^{ - 3}}$

Solution

(b) $pK_a = 5$, so $K_a = 1 \times {10^{ – 5}}$

$\alpha = \sqrt {\frac{{K_a}}{C}} = \sqrt {\frac{{1 \times {{10}^{ – 5}}}}{{0.1}}} = 1 \times {10^{ – 2}}$

Standard 11

Chemistry

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