The concentration of $[{H^ + }]$ and concentration of $[O{H^ - }]$ of a $ 0.1$ aqueous solution of $2\%$ ionised weak acid is [Ionic product of water $ = 1 \times {10^{ - 14}}]$
$2 \times {10^{ - 3}}$ $M$ and $5 \times {10^{ - 12}}$ $M$
$1 \times {10^3}\;M\;{\rm{and}}\;3 \times {10^{ - 11}}M$
$0.02 \times {10^{ - 3}}\;M\;{\rm{and}}\;5 \times {10^{ - 11}}M$
$3 \times {10^{ - 2}}\;M\;{\rm{and}}\;4 \times {10^{ - 13}}M$
Given the two concentration of $HCN (K_a = 10^{-9})$ are $0.1\,M$ and $0.001\,M$ respectively. What will be the ratio of degree of dissociation ?
The ionization constant of acetic acid is $1.74 \times 10^{-5}$. Calculate the degree of dissociation of acetic acid in its $0.05\, M$ solution. Calculate the concentration of acetate ion in the solution and its $pH$.
The $ pH$ of $ 0.1$ $M$ acetic acid is $3$, the dissociation constant of acid will be
For a concentrated solution of a weak electrolyte ( $K _{ eq }=$ equilibrium constant) $A _2 B _3$ of concentration ' $c$ ', the degree of dissociation " $\alpha$ ' is
At $25\,^o C$, the dissociation constant of a base $BOH$ is $1.0 \times {10^{ - 12}}$. The concentration of Hydroxyl ions in $0.01\, M$ aqueous solution of the base would be