$pH$ of an aqueous solution $H_2CO_3$ is $3.3$. If ${K_{{a_1}}} = {10^{ - 3}}$and ${K_{{a_2}}} = {10^{ - 13}}$ then $[HCO_3^-]$ is

  • A

    $5 \times {10^{ - 4}}\,M$

  • B

    $6 \times {10^{ - 5}}\,M$

  • C

    $3 \times {10^{ - 7}}\,M$

  • D

    $2 \times {10^{ - 3}}\,M$

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