$pH$ of an aqueous solution $H_2CO_3$ is $3.3$. If ${K_{{a_1}}} = {10^{ - 3}}$and ${K_{{a_2}}} = {10^{ - 13}}$ then $[HCO_3^-]$ is
$pH$ of an aqueous solution $H_2CO_3$ is $3.3$. If ${K_{{a_1}}} = {10^{ - 3}}$and ${K_{{a_2}}} = {10^{ - 13}}$ then $[HCO_3^-]$ is
- A
$5 \times {10^{ - 4}}\,M$
- B
$6 \times {10^{ - 5}}\,M$
- C
$3 \times {10^{ - 7}}\,M$
- D
$2 \times {10^{ - 3}}\,M$
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