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6-2.Equilibrium-II (Ionic Equilibrium)
medium
$pH$ of an aqueous solution $H_2CO_3$ is $3.3$. If ${K_{{a_1}}} = {10^{ - 3}}$and ${K_{{a_2}}} = {10^{ - 13}}$ then $[HCO_3^-]$ is
A
$5 \times {10^{ - 4}}\,M$
B
$6 \times {10^{ - 5}}\,M$
C
$3 \times {10^{ - 7}}\,M$
D
$2 \times {10^{ - 3}}\,M$
Solution
$[HCO_3^-] = [H^+]_{eff} = [H^+] = 10^{-3.3}$
$= 10^{-4} \times 5\, M$
Standard 11
Chemistry
