(a) An electrostatic field line is a continuous curve. That is, a field line cannot have sudden brea

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1. Electric Charges and Fields

medium

$(a)$ An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?

$(b)$ Explain why two field lines never cross each other at any point?

Option A

Option B

Option C

Option D

Solution

$(a)$ An electrostatic field line is a continuous curve because a charge experiences a continuous force when traced in an electrostatic field. The field line cannot have sudden breaks because the charge moves continuously and does not jump from one point to the other.

$(b)$ If two field lines cross each other at a point, then electric field intensity will show two directions at that point. This is not possible. Hence, two field lines never cross each other.

Standard 12

Physics

A cube is placed inside an electric field, $\overrightarrow{{E}}=150\, {y}^{2}\, \hat{{j}}$. The side of the cube is $0.5 \,{m}$ and is placed in the field as shown in the given figure. The charge inside the cube is $…..\times 10^{-11} {C}$

hard

(JEE MAIN-2021)

The spatial distribution of the electric field due to charges $(A, B)$ is shown in figure. Which one of the following statements is correct

normal

Why do electric field lines not form closed loop ?

medium

An electric line of force in the $xy$ plane is given by equation ${x^2} + {y^2} = 1$. A particle with unit positive charge, initially at rest at the point $x = 1,\;y = 0$ in the $xy$ plane

medium

(IIT-1988)

In a cuboid of dimension $2 L \times 2 L \times L$, a charge $q$ is placed at the centre of the surface ' $S$ ' having area of $4 L ^2$. The flux through the opposite surface to ' $S$ ' is given by

medium

(JEE MAIN-2023)

$(a)$ An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not? $(b)$ Explain why two field lines never cross each other at any point?

Solution

Similar Questions

A cube is placed inside an electric field, $\overrightarrow{{E}}=150\, {y}^{2}\, \hat{{j}}$. The side of the cube is $0.5 \,{m}$ and is placed in the field as shown in the given figure. The charge inside the cube is $…..\times 10^{-11} {C}$

The spatial distribution of the electric field due to charges $(A, B)$ is shown in figure. Which one of the following statements is correct

Why do electric field lines not form closed loop ?

An electric line of force in the $xy$ plane is given by equation ${x^2} + {y^2} = 1$. A particle with unit positive charge, initially at rest at the point $x = 1,\;y = 0$ in the $xy$ plane

In a cuboid of dimension $2 L \times 2 L \times L$, a charge $q$ is placed at the centre of the surface ' $S$ ' having area of $4 L ^2$. The flux through the opposite surface to ' $S$ ' is given by

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$(a)$ An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?

$(b)$ Explain why two field lines never cross each other at any point?