BCl₃ , exists as monomer whereas AlCl₃ is dimerized through halogen bridging. Give reason. Expla

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p-Block Elements - I

medium

$BCl_3$, exists as monomer whereas $AlCl_3$ is dimerized through halogen bridging. Give reason. Explain the structure of the dimer of $AlCl_3$ also.

Option A

Option B

Option C

Option D

Solution

$\mathrm{BCl}_{3}$ does not dimerize because of its small size. $\mathrm{BCl}_{3}$ do not exist as a dimer. Boron cannot accommodate four large sized chloride ions. $\mathrm{AlCl}_{3}$ exist as a dimer in which $\mathrm{Al}$ uses its vacant $3 p$-orbital by coordinate with $\mathrm{Cl}$ to complete their octet by forming dimer. $\mathrm{AlCl}_{3}$ achieves stability by forming a dimer.

Standard 11

Chemistry

Why does boron trifluoride behave as a Lewis acid ?

medium

Match List$-I$ with List$-II :$

List$-I$ List$-II$

$a$ Borax $i$ $NaBO _2$

$b$ Kernite $ii$ $Na _2 B _4 O _7 .4 H _2 O$

$c$ Orthoboric acid $iii$ $H _3 BO _3$

$d$ Borax bead $iv$ $Na _2 B _4 O _7 .10 H _2 O$

Choose the correct answer from the options given below :

medium

(NEET-2022)

A compound $(A)$ of boron reacts with $NMe_3$ to give an adduct $(B)$ which on hydrolysis gives a compound $(C) $ and hydrogen gas. Compound $(C)$ is an acid. Identify the compounds $A, B$ and $C.$ Give the reactions involved.

medium

Name the metals with which $Al$ can form alloy?

easy

Borax is converted into crystalline boron by the following steps

${B{orax}}\xrightarrow{X}{H_3}B{O_3}\xrightarrow{\Delta }{B_2}{O_3}\xrightarrow[\Delta ]{Y}B$,

$X$ and $Y$ are respectively

normal

List$-I$	List$-II$
$a$ Borax	$i$ $NaBO _2$
$b$ Kernite	$ii$ $Na _2 B _4 O _7 .4 H _2 O$
$c$ Orthoboric acid	$iii$ $H _3 BO _3$
$d$ Borax bead	$iv$ $Na _2 B _4 O _7 .10 H _2 O$

$BCl_3$, exists as monomer whereas $AlCl_3$ is dimerized through halogen bridging. Give reason. Explain the structure of the dimer of $AlCl_3$ also.

Solution

Similar Questions

Why does boron trifluoride behave as a Lewis acid ?

Match List$-I$ with List$-II :$ List$-I$ List$-II$ $a$ Borax $i$ $NaBO _2$ $b$ Kernite $ii$ $Na _2 B _4 O _7 .4 H _2 O$ $c$ Orthoboric acid $iii$ $H _3 BO _3$ $d$ Borax bead $iv$ $Na _2 B _4 O _7 .10 H _2 O$ Choose the correct answer from the options given below :

A compound $(A)$ of boron reacts with $NMe_3$ to give an adduct $(B)$ which on hydrolysis gives a compound $(C) $ and hydrogen gas. Compound $(C)$ is an acid. Identify the compounds $A, B$ and $C.$ Give the reactions involved.

Name the metals with which $Al$ can form alloy?

Borax is converted into crystalline boron by the following steps ${B{orax}}\xrightarrow{X}{H_3}B{O_3}\xrightarrow{\Delta }{B_2}{O_3}\xrightarrow[\Delta ]{Y}B$, $X$ and $Y$ are respectively

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Match List$-I$ with List$-II :$

List$-I$ List$-II$

$a$ Borax $i$ $NaBO _2$

$b$ Kernite $ii$ $Na _2 B _4 O _7 .4 H _2 O$

$c$ Orthoboric acid $iii$ $H _3 BO _3$

$d$ Borax bead $iv$ $Na _2 B _4 O _7 .10 H _2 O$

Choose the correct answer from the options given below :

Borax is converted into crystalline boron by the following steps

${B{orax}}\xrightarrow{X}{H_3}B{O_3}\xrightarrow{\Delta }{B_2}{O_3}\xrightarrow[\Delta ]{Y}B$,

$X$ and $Y$ are respectively