$BCl_3$, exists as monomer whereas $AlCl_3$ is dimerized through halogen bridging. Give reason. Explain the structure of the dimer of $AlCl_3$ also.
$\mathrm{BCl}_{3}$ does not dimerize because of its small size. $\mathrm{BCl}_{3}$ do not exist as a dimer. Boron cannot accommodate four large sized chloride ions. $\mathrm{AlCl}_{3}$ exist as a dimer in which $\mathrm{Al}$ uses its vacant $3 p$-orbital by coordinate with $\mathrm{Cl}$ to complete their octet by forming dimer. $\mathrm{AlCl}_{3}$ achieves stability by forming a dimer.
Consider the following statements for diborane
$1.$ Boron is approximately $sp^3$ hybridized
$2.$ $B-H-B$ angle is $180^o$
$3.$ There are two terminal $B-H$ bonds for each boron atom
$4.$ There are only $12$ bonding electrons available
Of these statements
Which of the following is correct
The reaction of $\mathrm{H}_{3} \mathrm{N}_{3} \mathrm{B}_{3} \mathrm{Cl}_{3}$ $(A)$ with $\mathrm{LiBH}_{4}$ in tetrahydrofurane gives inorganic benzene $(B)$. Further, the reaction of $(A)$ with $(C)$ leads to $\mathrm{H}_{3} \mathrm{N}_{3} \mathrm{B}_{3}(\mathrm{Me})_{3}$. than Compounds $(\mathrm{B})$ and $(\mathrm{C})$ respectively, are
Heating an aqueous solution of aluminium chloride to dryness will give
Aluminium is obtained by