${K_a} = 1.4 \times {10^{ - 5}}$ of propanoic acid. Calculate its $pH$ of $0.1$ $M$ solution.

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$\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=1.2 \times 10^{-3}, \mathrm{pH}=2.92$

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