{Kₐ} = 1.4 × {10^{ - 5}} of propanoic acid. Calculate its pH of 0.1 M solution.

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6-2.Equilibrium-II (Ionic Equilibrium)

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${K_a} = 1.4 \times {10^{ - 5}}$ of propanoic acid. Calculate its $pH$ of $0.1$ $M$ solution.

Option A

Option B

Option C

Option D

Solution

$\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=1.2 \times 10^{-3}, \mathrm{pH}=2.92$

Standard 11

Chemistry

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