10 ,mL of a solution of NaOH is found to be completely neutralised by 8 ,mL of a given solution of H

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2. Acids, Bases and Salts

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$10 \,mL$ of a solution of $NaOH$ is found to be completely neutralised by $8 \,mL$ of a given solution of $HCl$. If we take $20 \,mL$ of the same solution of $NaOH$, the amount of $HCl$ solution (the same solution as before) required to neutralise it will be ...... $mL$

A

$16$

B

$4$

C

$8$

D

$12$

Solution

$16\,mL$ of $HCl$ solution will be required.

Standard 10

Science

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