Operatorname{cosec} θ=frac{2}{√{3}}, then θ=ldots ldots ldots ldots

English

Gujarati

Hindi

8. Introduction to Trigonometry

easy

$\operatorname{cosec} \theta=\frac{2}{\sqrt{3}},$ then $\theta=\ldots \ldots \ldots \ldots$

A

$30$

B

$45$

C

$60$

D

$90$

Solution

$\operatorname{cosec} \theta=\frac{2}{\sqrt{3}} \, \therefore \sin \theta=\frac{\sqrt{3}}{2} .$

But, $\sin 60=\frac{\sqrt{3}}{2} \, \therefore \theta=60$

Standard 10

Mathematics

Share

Similar Questions

$\tan (65-\theta)-\cot (25-\theta)-\sec (55-\theta)+\operatorname{cosec}(35-\theta)=\ldots \ldots \ldots \ldots . .$ (where, $0 < \theta < 25)$

medium

$\left(1+\tan ^{2} \theta\right)\left(1-\cos ^{2} \theta\right)=\ldots \ldots \ldots$

easy

$\frac{\sin 60+\cos 30}{1+\sin 30+\cos 60}=\ldots \ldots \ldots$

easy

Prove that $\sin ^{6} \theta+\cos ^{6} \theta+3 \sin ^{2} \theta \cos ^{2} \theta=1$

medium

$2 \sin ^{2} \theta+4 \sec ^{2} \theta+5 \cot ^{2} \theta+2 \cos ^{2} \theta-4 \tan ^{2} \theta-5 \operatorname{cosec}^{2} \theta=\ldots \ldots \ldots$

medium