Cot θ=frac{a}{b}, then frac{cos θ-sin θ}{cos θ+sin θ}=ldots ldots ldots

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8. Introduction to Trigonometry

medium

$\cot \theta=\frac{a}{b},$ then $\frac{\cos \theta-\sin \theta}{\cos \theta+\sin \theta}=\ldots \ldots \ldots$

$\frac{a}{b}$

$\frac{b}{a}$

$\frac{a+b}{a-b}$

$\frac{a-b}{a+b}$

Solution

$\cot \theta=\frac{a}{b} \, \therefore \frac{\cos \theta}{\sin \theta}=\frac{a}{b} \, \therefore \frac{\cos \theta-\sin \theta}{\cos \theta+\sin \theta}=\frac{a-b}{a+b}$

Standard 10

Mathematics

$\sin \theta=\frac{3}{5},$ then $\tan \theta=\ldots \ldots \ldots \ldots$

easy

$\sin ^{2} 15+\sin ^{2} 75=\ldots \ldots \ldots \ldots$

easy

$\cos \theta=\frac{15}{17},$ then the value of $\operatorname{cosec} \theta+\cot \theta $ is ………

easy

If $\tan 7 \theta \cdot \tan 3 \theta=1,$ then the value of $\theta$ is ……….

medium

$\sin 60 \sin 45+\cos 60 \cos 45=\ldots \ldots \ldots \ldots$

easy

$\cot \theta=\frac{a}{b},$ then $\frac{\cos \theta-\sin \theta}{\cos \theta+\sin \theta}=\ldots \ldots \ldots$

Solution

Similar Questions

$\sin \theta=\frac{3}{5},$ then $\tan \theta=\ldots \ldots \ldots \ldots$

$\sin ^{2} 15+\sin ^{2} 75=\ldots \ldots \ldots \ldots$

$\cos \theta=\frac{15}{17},$ then the value of $\operatorname{cosec} \theta+\cot \theta $ is ………

If $\tan 7 \theta \cdot \tan 3 \theta=1,$ then the value of $\theta$ is ……….

$\sin 60 \sin 45+\cos 60 \cos 45=\ldots \ldots \ldots \ldots$

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