Left(1+tan ^{2} θright)left(1-cos ^{2} θright)=ldots ldots ldots

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8. Introduction to Trigonometry

easy

$\left(1+\tan ^{2} \theta\right)\left(1-\cos ^{2} \theta\right)=\ldots \ldots \ldots$

$\cot ^{2} \theta$

$\tan ^{2} \theta$

$1$

$0$

Solution

$\left(1+\tan ^{2} \theta\right)\left(1-\cos ^{2} \theta\right)=\sec ^{2} \theta \cdot \sin ^{2} \theta=\frac{\sin ^{2} \theta}{\cos ^{2} \theta}=\tan ^{2} \theta$

Standard 10

Mathematics

લઘૂકોણ $\theta$ માટે જો $\cos \theta=\sin \theta,$ તો $2 \tan ^{2} \theta+\sin ^{2} \theta+1=\ldots \ldots \ldots \ldots$

medium

$\sin \theta=\frac{1}{2},$ તો $\theta=\ldots \ldots \ldots \ldots$

easy

$\sin 70=\cos \theta,$ તો $\theta=\ldots \ldots \ldots \ldots$

easy

સાબિત કરો :

$(\sqrt{3}+ 1) \left(3-\cot 30^{\circ}\right)=\tan ^{3} 60^{\circ}-2 \sin 60^{\circ}$

medium

$\cos (40-\theta)-\sin (50+\theta)=\ldots \ldots \ldots \ldots$

easy

$\left(1+\tan ^{2} \theta\right)\left(1-\cos ^{2} \theta\right)=\ldots \ldots \ldots$

Solution

Similar Questions

લઘૂકોણ $\theta$ માટે જો $\cos \theta=\sin \theta,$ તો $2 \tan ^{2} \theta+\sin ^{2} \theta+1=\ldots \ldots \ldots \ldots$

$\sin \theta=\frac{1}{2},$ તો $\theta=\ldots \ldots \ldots \ldots$

$\sin 70=\cos \theta,$ તો $\theta=\ldots \ldots \ldots \ldots$

સાબિત કરો : $(\sqrt{3}+ 1) \left(3-\cot 30^{\circ}\right)=\tan ^{3} 60^{\circ}-2 \sin 60^{\circ}$

$\cos (40-\theta)-\sin (50+\theta)=\ldots \ldots \ldots \ldots$

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સાબિત કરો :

$(\sqrt{3}+ 1) \left(3-\cot 30^{\circ}\right)=\tan ^{3} 60^{\circ}-2 \sin 60^{\circ}$