{d over {dx}}log (log x) =

English

Gujarati

Hindi

Basic Maths

medium

${d \over {dx}}\log (\log x)$=

A${x \over {\log x}}$

B${{\log x} \over x}$

C${(x\log x)^{ - 1}}$

DNone of these

Solution

(c) $\frac{d}{{dx}}\log (\log x) = \frac{1}{x}.\frac{1}{{\log x}} = {(x\log x)^{ – 1}}$.

Standard 11

Physics

Share

Similar Questions

If $y = 1 + x + {{{x^2}} \over {2!}} + {{{x^3}} \over {3!}} + …..\infty ,$then ${{dy} \over {dx}} = $

medium

A particular straight line passes through origin and a point whose abscissa is double of ordinate of the point. The equation of such straight line is :

medium

If $y = 1 + x + {{{x^2}} \over {2\,!}} + {{{x^3}} \over {3\,!}} + ….. + {{{x^n}} \over {n\,!}}$, then ${{dy} \over {dx}} = $

medium

The coordinates of a particle moving in $XY$-plane vary with time as $x=4 t ^2 ; y=2 t$. The locus of the particle is a :-

medium

If $y = x + {1 \over x}$, then

medium