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2. Electric Potential and Capacitance
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$A B C$ is a right angled triangle situated in a uniform electric field $\vec{E}$ which is in the plane of the triangle. The points $A$ and $B$ are at the same potential of $15 \,V$ while the point $C$ is at a potential of $20 \,V . A B=3 \,cm$ and $B C=4 \,cm$. The magnitude of electric field is (in $S.I.$ Units)

A
$100$
B
$125$
C
$167$
D
$208$
Solution

(b)
$5=E\left(\frac{4}{100}\right)$
$E=125\,N / C$
Standard 12
Physics
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