{n^n}{left( {frac{{n + 1}}{2}} right)^{2n}} i | vedclass

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Question

(b) $y = {n^n}{\left( {\frac{{n + 1}}{2}} ight)^{2n}}$

Put $n = 2$, $y = {2^2}{\left( {\frac{3}{2}} ight)^4} = 4\,.\,\frac{{81}}{{8 	imes 2}}

Vedclass · Accepted Answer

$(b)$ and $(c)$ both

Vedclass · Answer

(b) $y = {n^n}{\left( {\frac{{n + 1}}{2}} ight)^{2n}}$

Put $n = 2$, $y = {2^2}{\left( {\frac{3}{2}} ight)^4} = 4\,.\,\frac{{81}}{{8 	imes 2}} = \frac{{81}}{4}	ilde - 20$

Option  $(a) = {\left( {\frac{{n + 1}}{2}} ight)^3} = \frac{{27}}{8} < y$

Option $(b)  = {\left( {\frac{{n + 1}}{2}} ight)^3} = \frac{{27}}{8} < y$

Option $(c)  = {(2!)^3} = 8 < y$

${n^n}{\left( {\frac{{n + 1}}{2}} \right)^{2n}}$ is

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