3 and 4 .Determinants and Matrices
easy

$A = \left[ {\begin{array}{*{20}{c}}5&{ - 3}\\2&4\end{array}} \right]$and $B = \left[ {\begin{array}{*{20}{c}}6&{ - 4}\\3&6\end{array}} \right],$ then $A - B = $

A

$\left[ {\begin{array}{*{20}{c}}{11}&{ - 7}\\5&{10}\end{array}} \right]$

B

$\left[ {\begin{array}{*{20}{c}}{ - 1}&{{\rm{ }}1}\\{ - 1}&{ - 2}\end{array}} \right]$

C

$\left[ {\begin{array}{*{20}{c}}{11}&7\\5&{ - 10}\end{array}} \right]$

D

$\left[ {\begin{array}{*{20}{c}}{12}&{ - 7}\\5&{ - 10}\end{array}} \right]$

Solution

(b) $A = \left[ {\begin{array}{*{20}{c}}5&{ – 3}\\2&4\end{array}} \right]$and $B = \left[ {\begin{array}{*{20}{c}}6&{ – 4}\\3&6\end{array}} \right]$,

$\therefore$ $A – B = \left[ {\begin{array}{*{20}{c}}{ – 1}&{\,\,\,1}\\{ – 1}&{ – 2}\end{array}} \right]$.

Standard 12
Mathematics

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