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10-1.Thermometry, Thermal Expansion and Calorimetry
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$50 \,gm$ ice at $0°C$ in insulator vessel, $50g$ water of $100°C$ is mixed in it, then final temperature of the mixture is (neglect the heat loss)
A
$10°C$
B
$0^\circ < < {T_m} < 20^\circ C$
C
$20°C$
D
Above $20°C$
Solution
(a) ${\theta _{{\rm{mix}}}} = \frac{{{\theta _W} – \frac{{{L_{\,i}}}}{{{C_W}}}}}{2} = \frac{{100 – \frac{{80}}{1}}}{2} = 10^\circ C$
Standard 11
Physics
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