A piece of ice (heat capacity = 2100 J kg^{-1} ^o C^{-1} and latent heat = 3.36 × 10^5 J

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10-1.Thermometry, Thermal Expansion and Calorimetry

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A piece of ice (heat capacity $=$ $2100$ $J kg^{-1}$ $^o C^{-1}$ and latent heat $=$ $3.36$ $×$ $10^5$ $J kg^{-1}$) of mass $m$ grams is at $-5^o C$ at atmospheric pressure. It is given $420$ $J$ of heat so that the ice starts melting. Finally when the ice-water mixture is in equilibrium, it is found that $1$ $gm$ of ice has melted. Assuming there is no other heat exchange in the process, the value of $m$ is ...... $gm$

A

$2$

B

$4$

C

$ 6$

D

$ 8$

Solution

By principle of calorimetry $m \times 2100 \times 5+10^{-3} \times 3.36 \times 10^{5}=420$

$\therefore m=8 g m$

Standard 11

Physics

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