$5$ boys and $5$ girls are sitting in a row randomly. The probability that boys and girls sit alternatively is
$5$ boys and $5$ girls are sitting in a row randomly. The probability that boys and girls sit alternatively is
- A
$5/126$
- B
$1/126$
- C
$4/126$
- D
$6/125$
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One die has two faces marked $1$ , two faces marked $2$ , one face marked $3$ and one face marked $4$ . Another die has one face marked $1$ , two faces marked $2$ , two faces marked $3$ and one face marked $4$. The probability of getting the sum of numbers to be $4$ or $5$ , when both the dice are thrown together, is
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