A bag contains 8 black and 7 white balls. Two balls are drawn at random. Then for which probability

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14.Probability

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A bag contains $8$ black and $7$ white balls. Two balls are drawn at random. Then for which the probability is more

A

Both balls are white

B

One ball is white and one is black

C

Both balls are black

D

All of the above are equals

Solution

(b) Probability that both balls are white $ = \frac{{{}^7{C_2}}}{{{}^{15}{C_2}}} = \frac{1}{5}$

Probability that both balls are black $ = \frac{{{}^8{C_2}}}{{{}^{15}{C_2}}} = \frac{4}{{15}}$

Probability that one ball is white and one is black $ = \frac{{{}^7{C_1} \times {}^8{C_1}}}{{{}^{15}{C_2}}} = \frac{8}{{15}}$.

Standard 11

Mathematics

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