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6-2.Equilibrium-II (Ionic Equilibrium)
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$HA$ એસિડનું આયોનાઇઝ $HA $ $\rightleftharpoons$ $ H^+ + A^-$ $1.0$ મોલર દ્રાવણની $pH = 5$ છે તો વિયોજન અચળાંક = ......

A

$10^{-10}$

B

$5$

C

$5 \times 10^{-8}$

D

$1 \times 10^{-5}$

Solution

$\begin{align}   {{\text{H}}^{+}}=\sqrt{{{K}_{a}}C}\,\,\,\,\,\,pH=5 \\   ({{10}^{-5}})=\sqrt{{{K}_{a}}\times 1}\,\,\,\,\,\,\,\,{{H}^{+}}={{10}^{-5}} \\   {{K}_{a}}={{10}^{-10}} \\ \end{align}$

Standard 11
Chemistry

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