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6-2.Equilibrium-II (Ionic Equilibrium)
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કયા અલ્પદ્રાવ્ય ક્ષાર માટે $k_{sp}$ તથા $S$ (દ્રાવ્યતા) વચ્ચેનો સંબંધ $S=(K_{SP}/4)^{1/3}$ વડે આપી શકાય.?

A

$Ba$$SO_4$

B

$Al_2(SO_4)_3$

C

$Hg_2$$Cl_2$

D

$Ag_3(P$$O_4$)

Solution

$BaSO_4\rightleftharpoons Ba^{2+} + SO_4^{2-}$      $k_{sp}=s^2 $   $\therefore s = \sqrt {{k_{sp}}} $

 

$Ca_3(PO_4)_2\rightleftharpoons 3Ca^{2+} + 2PO_4^{3-}$      $k_{sp}=(3S)^3\times  (2S)^2=108s^5$    $\therefore \,\,s\, = \,\,{\left( {\frac{{{K_{sp}}}}{{108}}} \right)^{1/5}}$

$Hg_2Cl_2\rightleftharpoons Hg_2^{2+}+2Cl^-$     $k_{sp} =  S \times (2s)^2 = 4s^3$  $\therefore \,\,\,s\,\, = \,\,{\left( {\frac{{{K_{sp}}}}{4}} \right)^{1/3}}$

$Ag_3PO_4  \rightleftharpoons   3Ag^++PO_4^{3-}$     $k_{sp} = (3s)^3 \times s = 27s^4$ $\therefore \,\,s\,\, = \,\,{\left( {\frac{{{K_{sp}}}}{{27}}} \right)^{1/4}}$

$Cus \rightleftharpoons  Cu^{2+}+s^{2-} \,\,,k_{sp}=s^2$ $\therefore \,\,s\,\, = \,\,\sqrt {ksp} $

Standard 11
Chemistry

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