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5.Work, Energy, Power and Collision
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એક પદાર્થનુંં વેગમાન વધીને $50\%$ થાય છે. તો પદાર્થની $K.E. $ વધીને કેટલા ........... $\%$ થશે ?
A
$50$
B
$125$
C
$330$
D
$400$
Solution
$\,{\text{P}}\,\, = \,\,\sqrt {{\text{2mE}}} \,\, \Rightarrow \,E\,\, \propto \,\,{p^2}$
$\,\frac{{{E_2}\,\, – \,\,{E_1}}}{{{E_1}}}\,\, \times \,\,\,100\,\, = \,\,\left( {\frac{{p_2^2\,\, – \,\,p_1^2}}{{p_1^2}}} \right)\,\, \times \,\,100$
% માં વધારો $ = \,\,\frac{{{{\left( {150} \right)}^2}\,\, – \,\,{{\left( {100} \right)}^2}}}{{{{\left( {100} \right)}^2}}}\,\, \times \,\,100 = \,\,\frac{{250\,\, \times \,\,50}}{{100}}\,\, = \,\,125\% $
Standard 11
Physics
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