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12.Kinetic Theory of Gases
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જો વાયુનો $r.m.s$ વેગ $v_{rms}$ = $1840 m/s$ અને ઘનતા $\rho$ = $8.99 \times 10^{-2} kg/m^3$, છે, તો દબાણ ?
A
$1.01 N/m^3$
B
$1.01 \times 10^3 N/m^3$
C
$1.01 \times 10^5 N/m^{2}$
D
$1.01 \times 10^7 N/m^{2}$
Solution
$\,{\upsilon _{rms}} = \sqrt {\frac{{3P}}{\rho }} \,\,$અથવા $P = \frac{{\rho V_{rms}^2}}{3} = \frac{{8.99 \times {{10}^{ – 2}} \times 1840 \times 1840}}{3} = 1.01 \times {10^5}N/{m^2}$
Standard 11
Physics
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