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13.Nuclei
easy
$_{13}Al^{27}$ અને $_{52}Te^{125 }$ ન્યુક્લિયસની ત્રિજ્યાના ગુણોત્તર શોધો.
A
$1 : 3$
B
$2 : 3$
C
$3 : 5$
D
$5 : 3$
Solution
$\,R\,\, \propto \,\,{A^{1/3}}\,$
$ \Rightarrow \,\,\,\,\frac{{{R_{Al}}}}{{{R_{Te}}}}\,\, = \,\,{\left( {\frac{{{A_{Al}}}}{{{A_{Te}}}}} \right)^{1/3}}\,$
$= \,\,\,{\left( {\frac{{27}}{{125}}} \right)^{1/3}} = \,\,{\left( {\frac{{{3^3}}}{{{5^3}}}} \right)^{1/3}} = \,\,\frac{3}{5}$
Standard 12
Physics