બે બિંદુવત વિદ્યુતભારો + 9 e અને +e એકબીજાથી | vedclass

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Question

Let the charge $q$ is placed at a distance $x$ from $+9 e$ and inbetween charges $+9 e$ and te

Using Coulomb's law,

$\frac{K \cdot 9 e \cdot

Vedclass · Accepted Answer

$+ 9\,e$ થી $12\, cm$

Vedclass · Answer

Let the charge $q$ is placed at a distance $x$ from $+9 e$ and inbetween charges $+9 e$ and te

Using Coulomb's law,

$\frac{K \cdot 9 e \cdot q}{x^2}=\frac{K \cdot q \cdot e}{(16-x)^2}\left\{F=\frac{K q_1 q_2}{r^2}ight\}$

$\left(\frac{16-x^2}{x}ight)^2=\frac{1}{9}$

$\frac{16}{x}-1=\pm \frac{1}{3}$

$\Rightarrow \frac{16}{x}=\frac{4}{3} 	ext { or } \frac{2}{3}$

$\Rightarrow x=\frac{3 	imes 16}{4} 	ext { or } \frac{3 	imes 16}{2}$

$	herefore x=12\,cm 	ext { or } 24\,cm$

As the charge $q$, can be equilibrium present only when its is kept inbetween charges $+9 e$ and $+e$, correct answer is $x=12\,cm$

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