Cs, Cl ના સામાન્ય સ્ફટકીના બંધારણમાં Cs^+ અને | vedclass

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Question

Step $1:$ Net force on $Cl ^{-}$ion at the centre

From Figure, Position of $Cl ^{-}$is symmetric at the centre, and distances of all $Cs ^{+}$ ions

Vedclass · Accepted Answer

$zero$

Vedclass · Answer

Step $1:$ Net force on $Cl ^{-}$ion at the centre

From Figure, Position of $Cl ^{-}$is symmetric at the centre, and distances of all $Cs ^{+}$ ions from center is same, so magnitude of all attraction forces on $Cl ^{-}$will also be same.

Therefore, all $Cs ^{+}$ions will attract $Cl ^{-}$at center with equal forces in opposite directions. So, all their forces will cancel out. Hence Net force on $Cl ^{-}$ion will be $zero$.

Therefore correct answer is $D$

Step $2$: Detailed Explanation of forces on $Cl ^{-}$

The forces on $Cl ^{-}$will be get cancelled due to equal and opposite forces.

Forces due to $1$ and $7$ will cancel

Forces due to $2$ and $8$ will cancel

Forces due to $3$ and $5$ will cancel

Forces due to $4$ and $6$ will cancel

So, Net force on $Cl ^{-}$will be zero

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