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Question

A hydrogen atom consists of an electron and a proton.

$	herefore$ Charge on one hydrogen atom

$=q_{e}+q_{p}=-e+(e+\Delta e)=\Delta e$

Since

Vedclass · Accepted Answer

$10^{-37 }\,\,C$

Vedclass · Answer

A hydrogen atom consists of an electron and a proton.

$	herefore$ Charge on one hydrogen atom

$=q_{e}+q_{p}=-e+(e+\Delta e)=\Delta e$

Since a hydrogen atom carry a net charge $\Delta e$

$	herefore \quad$ Electrostatic force,

$F_{e} \frac{1}{4 \pi \varepsilon_{o}} \frac{(\Delta e)^{2}}{d^{2}}.........(i)$

will act between two hydrogen atoms.

The gravitational force between two hydrogen atoms is given as

$F_{g}=\frac{G m_{h} m_{h}}{d^{2}}.........(ii)$

since, the net force on the system is zero, $F_{e}=F_{g}$ Using eqns. $(i)$ and $(ii)$, we get

${\frac{(\Delta e)^{2}}{4 \pi \varepsilon_{o} d^{2}}=\frac{G m_{h}^{2}}{d^{2}}}$

${(\Delta e)^{2}=4 \pi \varepsilon_{o} G m_{h}^{2}}$

${=6.67 	imes 10^{-11} 	imes\left(1.67 	imes 10^{-27}ight)^{2} /\left(9 	imes 10^{9}ight)}$

${\Delta e=10^{-37} \,\mathrm{C}}$

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