English
Hindi
1. Electric Charges and Fields
normal

$A$ ક્ષેત્રફળ અને $V$ સ્થિતિમાન તફાવતે રાખેલા અંતર ધરાવતા કેપેસિટ માટે એકમ કદ દીઠ ઊર્જા.. ....

A

$\frac{1}{2}{\varepsilon _0}\frac{{{V^2}}}{{{d^2}}}$

B

$\frac{1}{{2{\varepsilon _0}}}\frac{{{V^2}}}{{{d^2}}}$

C

$\frac{1}{2}C{V^2}$

D

$\frac{{{Q^2}}}{{2C}}$

Solution

એકમ કદ દીઠ ઉર્જા ${\text{(v) }}\, = \,\,\frac{{\text{1}}}{2}\,{\varepsilon _0}{E^2}$

$E\,\, = \,\,\frac{V}{d}\,\,\therefore \,\,v\,\, = \,\,\,\frac{1}{2}\,\,{ \in _0}\,\,\frac{{{V^2}}}{{{d^2}}}$

Standard 12
Physics

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